Compiling 32-bit vs 64-bit project using CMake

Question

How do I specify that CMake should use a different link_directories value depending on whether the target is 32-bit or 64-bit? For example, 32-bit binaries need

Answer 1

I know it's quite old question. But it's still on top when you search with Google "cmake 32 64". I have answer similar to user434507's answer but a little bit more readable in my opinion (I don't like if-else construction in cmake, it looks ugly):

math(EXPR BITS "8*${CMAKE_SIZEOF_VOID_P}")
set(BOOST_LIBRARY "/boost/win${BITS}/lib")
set(CMAKE_EXE_LINKER_FLAGS ${BOOST_LIBRARY})

This will point BOOST_LIBRARY path to /boost/win32/lib or /boost/win64/lib, depending on your architecture.

Answer 2

You do something along these lines

  if( CMAKE_SIZEOF_VOID_P EQUAL 8 )
    set( BOOST_LIBRARY "/boost/win64/lib" )
  else( CMAKE_SIZEOF_VOID_P EQUAL 8 )
    set( BOOST_LIBRARY "/boost/win32/lib" )
  endif( CMAKE_SIZEOF_VOID_P EQUAL 8 )
  set( CMAKE_EXE_LINKER_FLAGS ${BOOST_LIBRARY} )

Answer 3

Based on rominf I turned up following solution (for Windows). I install boost libraries into: C:\Boost_32 and C:\Boost_64

In CMakeLists.txt

math(EXPR BITS "8*${CMAKE_SIZEOF_VOID_P}")
set(BOOST_ROOT C:/Boost_${BITS})  

find_package(Boost 1.64.0 COMPONENTS ... )

INCLUDE_DIRECTORIES( ${Boost_INCLUDE_DIR}  )
LINK_DIRECTORIES(${Boost_LIBRARY_DIR})

Explanation:

• CMAKE_SIZEOF_VOID_P is equal to 4 on 32bit platform, and 8 on 64bit platform.
• Expression 8*${CMAKE_SIZEOF_VOID_P} will evaluate to 32 or 64, respectively.
• C:/Boost_${BITS} turns into C:/Boost_32 or C:/Boost_64 automagically

Advantages:

• You don't need conditionals (and in my CMakeLists there are too many already),
• It is 90% how you 'should' include Boost with CMake.

Answer 4

For Boost specifically, you should use

FIND_LIBRARY(Boost 1.44 COMPONENTS ...)

Then the CMake variable Boost_LIBRARY_DIRS will contain the correct library path, which has to be set using LINK_DIRECTORIES, e.g.

LINK_DIRECTORIES(${Boost_LIBRARY_DIRS})

The more general case is correctly described in user434507's answer.