Convert a delimted string to a dictionary in C#

Question

I have a string of the format \"key1=value1;key2=value2;key3=value3;\"

I need to convert it to a dictionary for the above mentioned key value pairs.

What wou

Answer 1

You could do this using JSON string, for example:

var dic = JsonConvert.DeserializeObject<Dictionary<int, string>>("{'1':'One','2':'Two','3':'Three'}");

Answer 2

You could write it like this or loop over it to do it yourself. Either way. Ultimately, you're splitting on ; to get the item pairs, then on = to get the key and value.

string input = "key1=value1;key2=value2;key3=value3;";
Dictionary<string, string> dictionary =
    input.TrimEnd(';').Split(';').ToDictionary(item => item.Split('=')[0], item => item.Split('=')[1]);

Loop version:

Dictionary<string, string> dictionary = new Dictionary<string, string>();
string[] items = input.TrimEnd(';').Split(';');
foreach (string item in items)
{
    string[] keyValue = item.Split('=');
    dictionary.Add(keyValue[0], keyValue[1]);
}

Answer 3

Something like this?

var dict = text.Split(new[] {';'}, StringSplitOptions.RemoveEmptyEntries)
               .Select(part => part.Split('='))
               .ToDictionary(split => split[0], split => split[1]);

Of course, this will fail if the assumptions aren't met. For example, an IndexOutOfRangeException could be thrown if the text isn't in the right format and an ArgumentException will be thrown if there are duplicate keys. Each of these scenarios will require different modifications. If redundant white-space could be present, you may need some string.Trim calls as necessary.

Answer 4

Behold the awesome whitespace ignoring, correcting for last value having or not having a semicolon power of regular expressions:

        var dict = Regex.Matches("key1 = value1; key2 = value2 ; key3 = value3", @"\s*(.*?)\s*=\s*(.*?)\s*(;|$)")
        .OfType<Match>()
        .ToDictionary(m => m.Groups[1].Value, m => m.Groups[2].Value);

But seriously though, Ani deserves props for the .ToDictionary(). I would never have thought of that.

Answer 5

Updated Ani's to take in account the semi colon at the end. The where clause will ensure that you have a key and value before creating and entry.

var dictionary = "key1=value1;key2=value2;key3=value3;"
    .Split(';')
    .Select (part  => part.Split('='))
    .Where (part => part.Length == 2)
    .ToDictionary (sp => sp[0], sp => sp[1]);