Greatest product of five consecutive digits in a 1000-digit number

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旧巷少年郎
旧巷少年郎 2020-12-24 11:15

I am working through the problems on project Euler and am not too certain if my understanding of the question is correct.

Problem 8 is as follows:

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  • 2020-12-24 11:38

    Only improvisation in my solution is, avoiding unnecessary computations by looking ahead.

    package com.euler;
    
    public class Euler8 {
        public static void main(String[] ar) throws Exception {
            String s = 
                    "73167176531330624919225119674426574742355349194934" + 
                    "96983520312774506326239578318016984801869478851843" + 
                    "85861560789112949495459501737958331952853208805511" + 
                    "12540698747158523863050715693290963295227443043557" + 
                    "66896648950445244523161731856403098711121722383113" + 
                    "62229893423380308135336276614282806444486645238749" + 
                    "30358907296290491560440772390713810515859307960866" + 
                    "70172427121883998797908792274921901699720888093776" + 
                    "65727333001053367881220235421809751254540594752243" + 
                    "52584907711670556013604839586446706324415722155397" + 
                    "53697817977846174064955149290862569321978468622482" + 
                    "83972241375657056057490261407972968652414535100474" + 
                    "82166370484403199890008895243450658541227588666881" + 
                    "16427171479924442928230863465674813919123162824586" + 
                    "17866458359124566529476545682848912883142607690042" + 
                    "24219022671055626321111109370544217506941658960408" + 
                    "07198403850962455444362981230987879927244284909188" + 
                    "84580156166097919133875499200524063689912560717606" + 
                    "05886116467109405077541002256983155200055935729725" + 
                    "71636269561882670428252483600823257530420752963450" ;
            Integer[] tokens = new Integer[s.length()];
            for (int i = 0; i < s.length(); i++) {
                tokens[i] = (int) s.charAt(i)-48;
            }
    
            int prod = 1;
            int[] numberSet = new int[5];
            int prodCounter = 1;
            for (int i=0; i<tokens.length-4; i++) {
                // Look ahead: if they are zeros in next 5 numbers, just jump.
                if ( tokens[i] == 0) {
                    i = i+1;
                    continue;
                } else if ( tokens[i+1] == 0) {
                    i = i+2;                
                    continue;
                } else if ( tokens[i+2] == 0) {
                    i = i+3;
                    continue;
                } else if ( tokens[i+3] == 0) {
                    i = i+4;                
                    continue;                           
                } else if ( tokens[i+4] == 0) {
                    i = i+5;                
                    continue;               
                }           
                int localProd = tokens[i] * tokens[i+1] * tokens[i+2] * tokens[i+3] * tokens[i+4];
                System.out.println("" + (prodCounter++) + ")" + tokens[i] + "*" + tokens[i+1] + "*" + tokens[i+2] + "*" + tokens[i+3] + "*" + tokens[i+4] + " = " + localProd);
                if (localProd > prod) {
                    prod = localProd;
                    numberSet[0] = tokens[i];
                    numberSet[1] = tokens[i+1];
                    numberSet[2] = tokens[i+2];
                    numberSet[3] = tokens[i+3];
                    numberSet[4] = tokens[i+4];
                }
            }
            System.out.println("Largest Prod = " + prod  + " By: (" + numberSet[0] + " , " + numberSet[1] + " ,  " + numberSet[2] + " , " + numberSet[3] + " , " + numberSet[4] + ")");
        }
    }
    
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  • 2020-12-24 11:39

    Five single digits. 1, 5, 8... whatever shows up in the big number, all in a row. So if a chunk read "...47946285..." Then you could use "47946", "79462", "94628", "46285", etc.

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  • 2020-12-24 11:46

    A digit is a single 0-9 in the string representing the number. So the number 12345 has 5 digits. 1234554321 has 10 digits.

    The product is the multiplicative total, not the added total. So the product of 3, 5 and 7 is 105.

    A (somewhat clunky) way of rephrasing the question would be:

    Given a 1000-digit number, select 5 consecutive digits from it that, when taken as individual numbers and multiplied together, give the largest result.

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