CGSize sizeWithAttributes in Swift

Question

In objective-C I was able to use:

    CGSize stringsize =
     [strLocalTelefone sizeWithAttributes:@{NSFontAttributeName:[UIFont systemFontOfSize:14.0f]}];
         


        

Answer 1

On xCode 8.0, this is what you need to do now: let charSize = string.size(attributes: [NSFontAttributeName: UIFont.systemFont(ofSize: 20)])

Answer 2

Just one line solution:

yourLabel.intrinsicContentSize.width for Objective-C / Swift

This will work even your label text have custom text spacing.

Answer 3

what I did is something like this:

swift 5.x

let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [.font: UIFont.systemFont(ofSize: 14)])

---

swift 4.x

let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [NSAttributedStringKey.font: UIFont.systemFont(ofSize: 14)])

---

swift 3

var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.size(attributes: [NSFontAttributeName: UIFont.systemFont(ofSize: 14.0)])

---

swift 2.x

var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])

Answer 4

You can also use this piece of code, it's easier and you don't have to create new variable just to get NSString object:

var stringToCalculateSize:String = "My text"
var stringSize:CGSize = (stringToCalculateSize as NSString).sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])

Answer 5

On xCode 6.3, this is what you need to do now:

    let font:AnyObject = UIFont(name: "Helvetica Neue", size: 14.0) as! AnyObject
    let name:NSObject = NSFontAttributeName as NSObject
    let dict = [name:font]
    let textSize: CGSize = text.sizeWithAttributes(dict)

Answer 6

Just use explicit casting:

var stringsize = (strLocalTelefone as NSString).sizeWithAtt...

Otherwise you can bridge it too:
Bridging is no longer supported in later versions of Swift.

var strLocalTelefone = "some string"
var stringsize = strLocalTelefone.bridgeToObjectiveC().sizeWithAttributes([NSFontAttributeName:UIFont.systemFontOfSize(14.0)])

This answer is worth at least looking at, as it highlights potential differences between the two approaches.