Purpose of return self python

Question

I have a problem with return self

class Fib: 
    def __init__(self, max):
        self.max = max
    def __iter__(self): 
        self.a = 0
           


        

Answer 1

This is needlessly complex code. Pay little attention to it. There's no reason on earth to implement it this way.

That being said, what it does is this:

class Fib: 

    """Implements the Fibonacci sequence."""

    def __init__(self, max_):
        self.max = max_

    def __iter__(self):
        """Initializes and returns itself as an iterable."""

        self.a = 0
        self.b = 1
        return self

    def __next__(self):
        """What gets run on each execution of that iterable."""

        fib = self.a
        if fib > self.max:
            raise StopIteration
        self.a, self.b = self.b, self.a + self.b  # increment
        return fib

This is all much easier to express as:

def fib(max_):
    a, b = 0, 1
    while b <= max_:
        out = a
        a, b = b, a+b
        yield out

Examples:

>>> fib_obj = Fib(20)
>>> for n in fib_obj:
...     print(n)

>>> for n in Fib(20):
...     print(n)

>>> for n in fib(20):
...     print(n)
# all give....
0
1
1
2
3
5
8
13

Answer 2

Returning self from a method simply means that your method returns a reference to the instance object on which it was called. This can sometimes be seen in use with object oriented APIs that are designed as a fluent interface that encourages method cascading. So, for example,

>>> class Counter(object):
...     def __init__(self, start=1):
...         self.val = start
...     def increment(self):
...         self.val += 1
...         return self
...     def decrement(self):
...         self.val -= 1
...         return self
...
>>> c = Counter()

Now we can use method cascading:

>>> c.increment().increment().decrement()
<__main__.Counter object at 0x1020c1390>

Notice, the last call to decrement() returned <__main__.Counter object at 0x1020c1390>, which is self. Now:

>>> c.val
2
>>>

Notice, you cannot do this if you did not return self:

>>> class Counter(object):
...     def __init__(self, start=1):
...         self.val = start
...     def increment(self):
...         self.val += 1
...         # implicitely return `None`
...     def decrement(self):
...         self.val -= 1
...         # implicitely return `None`
...
>>> c = Counter()
>>> c.increment().increment()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'NoneType' object has no attribute 'increment'
>>> c
<__main__.Counter object at 0x1020c15f8>
>>> c.val
2
>>>

Notice, not everyone is a fan of "method cascading" design. Python built-ins do not tend do this, so, list for example:

>>> x = list()
>>> x.append(1).append(2)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'NoneType' object has no attribute 'append'
>>>

The one place you do often see this is when your class implements the iterator protocol, where iter on an iterator returns self by convention, although this is suggested by the docs:

Having seen the mechanics behind the iterator protocol, it is easy to add iterator behavior to your classes. Define an __iter__() method which returns an object with a __next__() method. If the class defines __next__(), then __iter__() can just return self:

class Reverse:
    """Iterator for looping over a sequence backwards."""
    def __init__(self, data):
        self.data = data
        self.index = len(data)

    def __iter__(self):
        return self

    def __next__(self):
        if self.index == 0:
            raise StopIteration
        self.index = self.index - 1
        return self.data[self.index]

Notice, this in effect makes your iterator only useful for a single pass (as it should be to properly follow the iterator protocol):

>>> x = [1, 2, 3, 4]
>>> it = iter(x)
>>> list(it)
[1, 2, 3, 4]
>>> list(it)
[]
>>> next(it)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
StopIteration
>>>