How to compare Debian package versions?

Question

I looked at python-apt and python-debian, and they don\'t seem to have functionality to compare package versions. Do I have to write my own, or is

Answer 1

Perhaps because the title doesn't mention Python (though the tags do), Google brought me here when asking the same question but hoping for a bash answer. That seems to be:

$ dpkg --compare-versions 11a lt 100a && echo true
true
$ dpkg --compare-versions 11a gt 100a && echo true
$ 

To install a version of rubygems that's at least as new as the version from lenny-backports in a way that gives no errors on lenny and squeeze installations:

sudo apt-get install rubygems &&
VERSION=`dpkg-query --show --showformat '${Version}' rubygems` &&
dpkg --compare-versions $VERSION lt 1.3.4-1~bpo50+1 &&
sudo apt-get install -t lenny-backports rubygems

Perhaps I should have asked how to do that in a separate question, in the hope of getting a less clunky answer.

Answer 2

python-debian can do this too. It's used in an almost identical way to python-apt:

from debian import debian_support 

a = '1:1.3.10-0.3'
b = '1.3.4-1'
vc = debian_support.version_compare(a,b)
if vc > 0:
    print('version a > version b')
elif vc == 0:
    print('version a == version b')
elif vc < 0:
    print('version a < version b')

ouput:

version a > version b

Answer 3

You could use apt_pkg.version_compare:

import apt_pkg
apt_pkg.init_system()

a = '1:1.3.10-0.3'
b = '1.3.4-1'
vc = apt_pkg.version_compare(a,b)
if vc > 0:
    print('version a > version b')
elif vc == 0:
    print('version a == version b')
elif vc < 0:
    print('version a < version b')        

yields

version a > version b

---

Thanks to Tshepang for noting in the comments that for newer versions: apt.VersionCompare is now apt_pkg.version_compare.