How to get year and month from a date - PHP

Question

How to get year and month from a given date.

e.g. $dateValue = \'2012-01-05\';

From this date I need to get year as 2012

Answer 1

I'm using these function to get year, month, day from the date

you should put them in a class

    public function getYear($pdate) {
        $date = DateTime::createFromFormat("Y-m-d", $pdate);
        return $date->format("Y");
    }

    public function getMonth($pdate) {
        $date = DateTime::createFromFormat("Y-m-d", $pdate);
        return $date->format("m");
    }

    public function getDay($pdate) {
        $date = DateTime::createFromFormat("Y-m-d", $pdate);
        return $date->format("d");
    }

Answer 2

$dateValue = '2012-01-05';
$year = date('Y',strtotime($dateValue));
$month = date('F',strtotime($dateValue));

Answer 3

You can use this code:

$dateValue = strtotime('2012-06-05');
$year = date('Y',$dateValue);
$monthName = date('F',$dateValue);
$monthNo = date('m',$dateValue);
printf("m=[%s], m=[%d], y=[%s]\n", $monthName, $monthNo, $year);

Answer 4

Probably not the most efficient code, but here it goes:

$dateElements = explode('-', $dateValue);
$year = $dateElements[0];

echo $year;    //2012

switch ($dateElements[1]) {

   case '01'    :  $mo = "January";
                   break;

   case '02'    :  $mo = "February";
                   break;

   case '03'    :  $mo = "March";
                   break;

     .
     .
     .

   case '12'    :  $mo = "December";
                   break;


}

echo $mo;      //January