How to get year and month from a date - PHP

Question

How to get year and month from a given date.

e.g. $dateValue = \'2012-01-05\';

From this date I need to get year as 2012

Answer 1

I personally prefer using this shortcut. The output will still be the same, but you don't need to store the month and year in separate variables

$dateValue = '2012-01-05';
$formattedValue = date("F Y", strtotime($dateValue));
echo $formattedValue; //Output should be January 2012

A little side note on using this trick, you can use comma's to separate the month and year like so:

$formattedValue = date("F, Y", strtotime($dateValue));
echo $formattedValue //Output should be January, 2012

Answer 2

Use strtotime():

$time=strtotime($dateValue);
$month=date("F",$time);
$year=date("Y",$time);

Answer 3

I will share my code:

In your given example date:

$dateValue = '2012-01-05';

It will go like this:

dateName($dateValue);



   function dateName($date) {

        $result = "";

        $convert_date = strtotime($date);
        $month = date('F',$convert_date);
        $year = date('Y',$convert_date);
        $name_day = date('l',$convert_date);
        $day = date('j',$convert_date);


        $result = $month . " " . $day . ", " . $year . " - " . $name_day;

        return $result;
    }

and will return a value: January 5, 2012 - Thursday

Answer 4

$dateValue = '2012-01-05';
$yeararray = explode("-", $dateValue);

echo "Year : ". $yeararray[0];
echo "Month : ". date( 'F', mktime(0, 0, 0, $yeararray[1]));

Usiong explode() this can be done.

Answer 5

$dateValue = strtotime($q);

$yr = date("Y", $dateValue) ." "; 
$mon = date("m", $dateValue)." "; 
$date = date("d", $dateValue); 

Answer 6

Using date() and strtotime() from the docs.

$date = "2012-01-05";

$year = date('Y', strtotime($date));

$month = date('F', strtotime($date));

echo $month