Change backslash to forward slash in windows batch file

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醉话见心 2020-12-24 06:26

I\'m trying to convert all backslashes () to forward slashes (/) in a variable which contains a file name and location. I\'ve read about this and seen:

%vari         


        
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  • 2020-12-24 06:30

    This seems to work for me:

    echo off
    
    setlocal enabledelayedexpansion
    
    FOR %%f IN ("C:\tools\workspace\*") DO (
      set old=%%f
      echo !old!
      set new=!old:\=/!
      echo !new!  
      echo.                 
    )
    

    Using a seperate variable rather than the loop variable makes the difference, along with enabling delayed expansion as the variable substittion syntex using the loop variable %%f dosn't seem to work.

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  • 2020-12-24 06:35

    This will change the back-slashes to forward-slashes in a variable:

    set "variable=E:\myfiles\app1\data\*.csv"
    set "variable=%variable:\=/%"
    echo "%variable%"
    
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  • 2020-12-24 06:44

    Within a block statement (a parenthesised series of statements), the entire block is parsed and then executed. Any %var% within the block will be replaced by that variable's value at the time the block is parsed - before the block is executed - the same thing applies to a FOR ... DO (block).

    Hence, IF (something) else (somethingelse) will be executed using the values of %variables% at the time the IF is encountered.

    Two common ways to overcome this are 1) to use setlocal enabledelayedexpansion and use !var! in place of %var% to access the changed value of var or 2) to call a subroutine to perform further processing using the changed values.

    Note therefore the use of CALL ECHO %%var%% which displays the changed value of var.

    Your code contains two separate variables called f.

    The first is the loop-control 'metavariable' called f and referenced by %%f.

    The second is the common environment variable f which is established by the set "f=..." statement. This variable can be accessed by using %f% but within a block, it will appear to retain the value it had when the controlling for was parsed (in fact, any %var% is replaced at parse-time by the value of var at that time)

    metavariables cannot be used in string-manipulation statements like substrings or substitutes, only common environment variables can be used for these operations, hence you need to assign the value of the metavariable f to the environment variable f and then perform the string-substitution task of the environment variable f.

    The twist, of course, is that you must use delayedexpansion and the !var! syntax to access the modified value of an environment variable within a block.

    So,

    setlocal enabledelayedexpansion
    for...%%f...do (
      echo %%f
      set "f=%%f"
      set "f=!f:\=/!"
      echo !f!
    )
    echo just for demonstration %f% !f! %%f
    

    This sets the value of f in the required manner (of course, you could always change the name to avoid confusion...)

    The last line is simply to show that the final value acquired by f can be accessed outside of the loop as either %f% or !f!, and that %%f is out-of-context and shown as %f.

    Another way to do this without delayedexpansion is

    for...%%f...do (
      echo %%f
      set "f=%%f"
      call set "f=%%f:\=/%%"
      call echo %%f%%
    )
    echo just for demonstration %f% !f! %%f
    

    the difference being the use of call and doubling the %s, and the final line will show !f! as just that - a literal, since outside of delayedexpansion mode, ! is just another character with no special meaning to cmd.

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  • 2020-12-24 06:46

    Magoo's helpful answer shows how to perform dynamic substitutions (via delayed expansion) inside a for loop's (...) block.

    foxidrive's answer shows the general cmd syntax for performing literal, global string substitutions in variable values (also briefly shown in the question).

    Let me complement these answer with a solution that uses PowerShell's CLI:

    Note:

    • In the simple case at hand, this is overkill, and also performs worse than a pure cmd solution.

    • However, the technique can be helpful if you need more sophisticated, regex-based string substitutions, via PowerShell's regex-based -replace operator.

    @echo off
    
    :: Sample path.
    Set inPath=C:\foo\bar
    
    for /f "usebackq delims=" %%i in (
      `powershell -noprofile -c "\"%inPath%\" -replace '\\', '/'"`
    ) do set "outPath=%%i"
    
    echo %outPath%
    

    The above yields:

    C:/foo/bar
    

    In-line variant, with the input path directly embedded and direct output of the transformed string:

    C:\>powershell -noprofile -c "\"C:\foo\bar\" -replace '\\', '/'"
    C:/foo/bar
    
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  • 2020-12-24 06:52

    This will work for change the backslashe to forward slashes in windows:

     typedef std::basic_string<TCHAR> tstring;
     tstring pathbasic = tstring(programdata) + _T("\\myfile.txt");
     std::replace(pathbasic.begin(), pathbasic.end(), _T('\\'), _T('/'));
    
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