Angular Resource calls and $q

Question

Folks,

I have my code setup somewhat as below:

$scope.init = function(){
  return $q.all([resource1.query(),resource2.query(),resource3.query()])
            


        

Answer 1

For those still trying to figure out a better way to go about this, try this:

  resource.query().$promise.then(function(result) {
    console.log(result);
    // Do something else, like instantiate a JS driven table
  });

Answer 2

Like @cdidyks answer this utilises $promise, but in my opinion it is a better design pattern as it doesn't rely on all resources to be completed for assignment, and makes the $promises more accessible in less code.

$scope.data1 = resource1.query();
$scope.data2 = resource2.query();
$scope.data3 = resource3.query();

$scope.init = function() {
  return $q.all([
      $scope.data1.$promise,
      $scope.data2.$promise,
      $scope.data3.$promise
    ])
    .then(function(result) {
        console.log('all done');
      doSomething($scope.data1, $scope.data2);
    })
}

Answer 3

I ran into this problem, and it was quite confusing. The problem appears to be that calling a resource action doesn't actually return an http promise, but an empty reference (that is populated when the data returns from the server -see the return value section of the $resource docs).

I'm not sure why this results in .then(result) returning an array of unresolved promises, but to get each resource's promise, you need to use resource1.query().$promise. To re-write your example:

$scope.init = function() {
  return $q.all([resource1.query().$promise, resource2.query().$promise, resource3.query().$promise])
           .then( function(result) {
             $scope.data1 = result[0];
             $scope.data2 = result[1];
             $scope.data3 = result[2];

             console.log($scope.data1);

             doSomething($scope.data1,$scope.data2); 
           })
}

I hope that saves someone else some time.

Answer 4

you are printing data1 not $scope.data1

console.log(data1);

if i were you i would use it as follows

$scope.init = function(){
return $q.all([resource1.query(),resource2.query(),resource3.query()])
        .then(result){
          console.log(result[1]);
           $scope.data1 = result[1];
           $scope.data2 = result1[2];
           $scope.data3 = result[3];

           doSomething($scope.data1,$scope.data2); 
             }
}