JQGrid, change row background color based on condition

Question

I have the following jqgrid that uses the jquery ui theme imported to my master page.

  $(\"#shippingscheduletable\").jqGrid({
            url: $(\"#shipping         


        

Answer 1

Just for reference of others here is the completed code. I also found I needed to add another condition to change the color of the row. I needed to change the row color only when the paid field is true, and when the status is complete. This code shows that. It also fixed the problem of losing the formatting when the grid is reloaded when sorting the columns. I hope this helps someone else.

    var rowsToColor = [];
    jQuery(function () {
        $("#shippingscheduletable").jqGrid({
            url: $("#shippingscheduleurl").attr('href'),
            datatype: 'json',
            mtype: 'GET',
            altRows: true,
            colNames: ['Dealer', 'Model', 'Invoice', 'Date', 'PO', 'Serial', 'Status', 'City', 'State', 'Paid', 'Promo', 'Carrier', 'Int Notes', 'Ord Notes', 'Terms'],
            colModel: [
     { name: 'Company', index: 'id', width: 125, align: 'left' },
     { name: 'Model', index: 'Model', width: 50, align: 'left' },
     { name: 'Invoice', index: 'Invoice', width: 50, align: 'left' },
     { name: 'Date', index: 'OrderDate', width: 60, align: 'left' },
     { name: 'Po', index: 'PONum', width: 75, align: 'left' },
     { name: 'Serial', index: 'Serial', width: 50, align: 'left' },
     { name: 'Status', index: 'OrderStatus', width: 70, align: 'left' },
     { name: 'City', index: 'City', width: 100, align: 'left' },
     { name: 'State', index: 'State', width: 30, align: 'left' },
     { name: 'Paid', index: 'IsPaid', width: 30, align: 'left', formatter: rowColorFormatter },
     { name: 'Promo', index: 'Promo', width: 50, align: 'left' },
     { name: 'Carrier', index: 'Carrier', width: 80, align: 'left' },
     { name: 'InternalNotes', index: 'InternalNotes', width: 110, align: 'left' },
     { name: 'OrderNotes', index: 'OrderNotes', width: 110, align: 'left' },
     { name: 'Terms', index: 'Terms', width: 60, align: 'left' }
     ],
            pager: jQuery("#shippingschedulepager"),
            rowNum: 100,
            rowList: [100, 150, 200],
            sortname: 'Company',
            sortorder: "asc",
            viewrecords: true,
            height: '700px',
            multiselect: true,
            gridComplete: function () {
                for (var i = 0; i < rowsToColor.length; i++) {
                    var status = $("#" + rowsToColor[i]).find("td").eq(7).html();
                    if (status == "Complete") {
                        $("#" + rowsToColor[i]).find("td").css("background-color", "green");
                        $("#" + rowsToColor[i]).find("td").css("color", "silver");
                    }
                }
             }
        });
    });

    function rowColorFormatter(cellValue, options, rowObject) {
        if (cellValue == "True")
            rowsToColor[rowsToColor.length] = options.rowId;
        return cellValue;
    }

so the formatter function adds the rowid that needs to be changed to an array if the paid value is true, then when the grid is complete it changes the css for each row id, after it checks the value of the 7th td which is where my status is found to make sure it is complete.

Answer 2

use formatter function :

like in this post

http://www.trirand.net/forum/default.aspx?g=posts&m=2678

Answer 3

I used the a simple JQuery selector and applied my wanted styles. All you need is the uid (rowid) of the row you wish to apply the styles to.

if (!xCostCenter[i].saveSuccessful)
{  
    $("#row" + _updatedRowIDs[i] + "jqxgrid > div").css({ "background-color": "rgb(246, 119, 119)" });
}

In my case I wanted to change the color of rows that were not saved to change to a red color. To remove the color just execute the following.

$("#contenttablejqxgrid > div > div").css({ "background-color": "" });

hope this helps someone.

Answer 4

To paint the grid, use the function below. For example: PintarRowGrilla('#gridPreSeleccion', 3, 9, '#8FD9F1'); 9--> number of columns your grid:

function PintarRowGrilla(idGrilla, idrow, nrocolumnas, color)
{
    while(nrocolumnas > 0)
    {
        nrocolumnas--;
        jQuery(idGrilla).setCell(idrow, nrocolumnas, '', {
            'background-color': color
        });
    }
}

Answer 5

 loadComplete: function() {
    var ids = $(this).jqGrid("getDataIDs"), l = ids.length, i, rowid, status;
        for (i = 0; i < l; i++) {
        rowid = ids[i];
    // get data from some column "ColumnName"
        varColumnName= $(this).jqGrid("getCell", rowid, "ColumnName");
    // or get data from some 
    //var rowData = $(this).jqGrid("getRowData', rowid);

    // now you can set css on the row with some
        if (varColumnName=== condition) {
            $('#' + $.jgrid.jqID(rowid)).addClass('myAltRowClass');
         }
    }
},

Answer 6

Use JQGrid row event jqGridRowAttr for setting any formatting. For more detail see http://www.trirand.com/blog/?page_id=393/help/rowattr-triger-after-setrowdata Example steps to setting background are:

First set your custom CSS for conditional formatting inline or your CSS file. For example (Please see result in chrome browser)

.bg-danger {
  background-color: #f2dede;
}
.bg-danger td{ background-color : #ff0000ad; }

Add row event right after ColModel

rowattr: function (rd) {

                    if (rd.FileExists == 'no') // your condition here
                    {
                        return { "class": "bg-danger" };
                    }

                }