Combine (join) networkx Graphs

Question

Say I have two networkx graphs, G and H:

G=nx.Graph()
fromnodes=[0,1,1,1,1,1,2]
tonodes=[1,2,3,4,5,6,7]
for x,y in zip(fromnodes,ton         


        

Answer 1

The function you're looking for is compose, which produces a graph with all the edges and all the nodes that are in both graphs. If both graphs have a node with the same name, then a single copy ends up in the new graph. Similarly if the same edge exists in both. Here's an example, including edge/node attributes:

import networkx as nx

G=nx.Graph()
G.add_node(1, weight = 2)
G.add_node(2, weight = 3)
G.add_edge(1,2, flux = 5)
G.add_edge(2,4)

H=nx.Graph()
H.add_node(1, weight = 4)
H.add_edge(1,2, flux = 10)
H.add_edge(1,3) 

F = nx.compose(G,H)
#F has all nodes & edges of both graphs, including attributes
#Where the attributes conflict, it uses the attributes of H.

G.nodes(data=True)
> NodeDataView({1: {'weight': 2}, 2: {'weight': 3}, 4: {}})
H.nodes(data=True)
> NodeDataView({1: {'weight': 4}, 2: {}, 3: {}})
F.nodes(data=True)
> NodeDataView({1: {'weight': 4}, 2: {'weight': 3}, 4: {}, 3: {}})

G.edges(data=True)
> EdgeDataView([(1, 2, {'flux': 5}), (2, 4, {})])
H.edges(data=True)
> EdgeDataView([(1, 2, {'flux': 10}), (1, 3, {})])
F.edges(data=True)
EdgeDataView([(1, 2, {'flux': 10}), (1, 3, {}), (2, 4, {})])

These preserve attributes, but obviously if there is a conflict this is not possible. The attributes of H take precedence.

There are also other options to do the symmetric difference, intersection, ...

If you have multiple graphs to join together, you can use compose_all, which just wraps a for loop around compose.

Answer 2

This did it.

   U=nx.Graph()
   U.add_edges_from(G.edges()+H.edges())
   U.add_nodes_from(G.nodes()+H.nodes()) #deals with isolated nodes

or, preserving the edge attributes:

   U.add_edges_from(G.edges(data=True)+H.edges(data=True))

and, to also preserve the node attributes:

   U.add_nodes_from(G.nodes(data=True)+H.nodes(data=True))

Answer 3

In case you want to add graph H to G then return G, you can use update method.