How to get the start and end times of a day

Question

In my C# app, I pass a string variable that is of format yyyymmdd-yyyymmdd that represents a from and to date. I want to get the start and end times for these dates respecti

Answer 1

public static class DateTimeExtension {        
    public static DateTime StartOfTheDay(this DateTime d) => new DateTime(d.Year, d.Month, d.Day, 0, 0,0);
    public static DateTime EndOfTheDay(this DateTime d) => new DateTime(d.Year, d.Month, d.Day, 23, 59,59);
}

Answer 2

In Java 8, you can do it using LocalDate as follows:

    LocalDate localDateStart = LocalDate.now();
    Date startDate = Date.from(localDateStart.atStartOfDay(ZoneId.systemDefault()).toInstant());

    LocalDate localDateEnd = localDateStart.plusDays(1);
    Date endDate = Date.from(localDateEnd.atStartOfDay(ZoneId.systemDefault()).toInstant());

Answer 3

I use the following in C#

public static DateTime GetStartOfDay(DateTime dateTime)
{
    return new DateTime(dateTime.Year, dateTime.Month, dateTime.Day, 0, 0, 0, 0);
}
public static DateTime GetEndOfDay(DateTime dateTime)
{
    return new DateTime(dateTime.Year, dateTime.Month, dateTime.Day, 23, 59, 59, 999);
}

Then in MS SQL I do the following:

if datepart(ms, @dateEnd) = 0
   set @dateEnd = dateadd(ms, -3, @dateEnd)

This will result in MS SQL time of 23:59:59.997 which is the max time before becoming the next day.

You could simply use:

new DateTime(dateTime.Year, dateTime.Month, dateTime.Day, 23, 59, 59, 999);

Which will work in MS SQL, but this is not as accurate in .Net side.

Answer 4

That's pretty much what I would do, with some small tweaks (really no big deal, just nitpicking):

• The TryParse()/TryParseExact() methods should be used which return false instead of throwing exceptions.
• FormatException is more specific than Exception
• No need to check for Length == 8, because ParseExact()/TryParseExact() will do this
• "00:00:00" and "23:59:59" are not needed
• return true/false is you were able to parse, instead of throwing an exception (remember to check value returned from this method!)

Code:

private bool ValidateDatePeriod(string pdr, out DateTime startDate, 
                        out DateTime endDate)
{
   string[] dates = pdr.Split('-');

   if (dates.Length != 2)
   {
       return false;
   }

   // no need to check for Length == 8 because the following will do it anyway
   // no need for "00:00:00" or "23:59:59" either, I prefer AddDays(1)

   if(!DateTime.TryParseExact(dates[0], "yyyyMMdd", null, DateTimeStyles.None, out startDate))
      return false;

   if(!DateTime.TryParseExact(dates[1], "yyyyMMdd", null, DateTimeStyles.None, out endDate))
      return false;

   endDate = endDate.AddDays(1);
   return true;
}

Answer 5

The DateTime object has a property called Date which will return just the date portion. (The time portion is defaulted to 12:00 am).

I would recommend as a more elegant solution (IMHO) that if you want to allow any datetime on the last day, then you add 1 day to the date, and compare to allow times greater than or equal to the start date, but strictly less than the end date (plus 1 day).

// Calling code.  beginDateTime and endDateTime are already set.
// beginDateTime and endDateTime are inclusive.
// targetDateTime is the date you want to check.
beginDateTime = beginDateTime.Date;
endDateTime = endDateTime.Date.AddDays(1);

if ( beginDateTime <= targetDateTime &&
     targetDateTime < endDateTime )
   // Do something.

Answer 6

You could define two extension methods somewhere, in a utility class like so :

public static DateTime EndOfDay(this DateTime date)
{
    return new DateTime(date.Year, date.Month, date.Day, 23, 59, 59, 999);
}

public static DateTime StartOfDay(this DateTime date)
{
    return new DateTime(date.Year, date.Month, date.Day, 0, 0, 0, 0);
}

And then use them in code like so :

public DoSomething()
{
    DateTime endOfThisDay = DateTime.Now.EndOfDay();
}