Find PHP version on windows command line

Question

I just tried to know version of my PHP from windows command typing, C:\\> php -v But it is not working. It says php is not recognized as internal or ex

Answer 1

It is most likely that php is not in your specified path.

Try to issue the php command with the full path, for example:

C:\> "C:\Program Files\php\php.exe" -v

Please note, that this is just an example, your php installation might be in a different directory.

Answer 2

Easiest way is to, just click on the WAMP icon on task bar and Go to PHP >Version, version will be displayed

Answer 3

xampp control panel->shell->type php-v you get the version of php of your xampp installed

DB(mariadb/mysql)version type localhost/phpmyadmin in url click enter click on sql type select version(); enter to get the mysql or mariaDb version

Answer 4

For Beginners to anything php, it is usually stored in the C:/ path folder of your PC (My Computer).

==On Windows==
1.Click Start Menu button
2.Type cmd and press enter to select the first program/application that responds to your search result.
A black window terminal will appear, this is known as a Command Line Interpreter
3.In the Terminal Window (Application) Type cd c: and press enter
4.Now type php -v and press enter

and viola there you'll have the current php version that is installed in your machine

Answer 5

For me, the PHP path traversed from php5.6.25 (or php7) installation folder, through wamp folder, bin and php...

C:\wamp64\bin\php\php5.6.25>

Answer 6

This how I check php version

PS C:\Windows\system32> php -version

Result:

PHP 7.2.7 (cli) (built: Jun 19 2018 23:44:15) ( NTS MSVC15 (Visual C++ 2017) x86 )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.2.0, Copyright (c) 1998-2018 Zend Technologies

PS C:\Windows\system32>