Why does Firebug say toFixed() is not a function?

Question

I am using jQuery 1.7.2 and jQuery UI 1.9.1. I am using the code below within a slider. (http://jqueryui.com/slider/)

I have a function that should test two values a

Answer 1

toFixed isn't a method of non-numeric variable types. In other words, Low and High can't be fixed because when you get the value of something in Javascript, it automatically is set to a string type. Using parseFloat() (or parseInt() with a radix, if it's an integer) will allow you to convert different variable types to numbers which will enable the toFixed() function to work.

var Low  = parseFloat($SliderValFrom.val()),
    High = parseFloat($SliderValTo.val());

Answer 2

You need convert to number type:

(+Low).toFixed(2)

Answer 3

That is because Low is a string.

.toFixed() only works with a number.

---

Try doing:

Low = parseFloat(Low).toFixed(..);

Answer 4

Low is a string.

.toFixed() only works with a number.

A simple way to overcome such problem is to use type coercion:

Low = (Low*1).toFixed(..);

The multiplication by 1 forces to code to convert the string to number and doesn't change the value. JSFiddle code here.

Answer 5

In a function, use as

render: function (args) {
    if (args.value != 0)
        return (parseFloat(args.value).toFixed(2));


},