How to stop an image from stretching within a UIImageView?

Question

I have a UIImageView where I have set the frame size to x = 0, y = 0, width = 404, height = 712. In my project, I need to change the image in

Answer 1

Update for Swift 3:

imageView.contentMode = .scaleAspectFit

Answer 2

Use the contentMode property. You probably want either UIViewContentModeScaleAspectFit or UIViewContentModeCenter.

Answer 3

Setting clipsToBounds in combination with UIViewContentModeScaleAspectFit contentMode was what did the trick for me. Hope that helps someone!

imageView.clipsToBounds = YES;
imageView.contentMode = UIViewContentModeScaleAspectFit;

Answer 4

You can use

self.imageView.contentMode = UIViewContentModeScaleAspectFit;

Swift 3:

imageView.contentMode = .scaleAspectFit

Or UIViewContentModeCenter / .center, or any of the other modes described in the UIView documentation.

Answer 5

You have to set CGSize as your image width and hight so image will not stretch and it will arrange at the middle of imageview.

- (UIImage *)imageWithImage:(UIImage *)image scaledToFillSize:(CGSize)size
{
    CGFloat scale = MAX(size.width/image.size.width, size.height/image.size.height);
    CGFloat width = image.size.width * scale;
    CGFloat height = image.size.height * scale;
    CGRect imageRect = CGRectMake((size.width - width)/2.0f,
                                  (size.height - height)/2.0f,
                                  width,
                                  height);

    UIGraphicsBeginImageContextWithOptions(size, NO, 0);
    [image drawInRect:imageRect];
    UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();
    UIGraphicsEndImageContext();
    return newImage;
}

Answer 6

Use this for your UIImageView

imageView.contentMode = UIViewContentModeScaleAspectFill;

You won't get any space and with scale preserved. However, some part of the image will be clipped off.

If you use the following:

imageView.contentMode = UIViewContentModeScaleAspectFit;

There will be some empty space, but scale is preserved.