Create a List that contain each Line of a File

Question

I\'m trying to open a file and create a list with each line read from the file.

   i=0
   List=[\"\"]
   for Line in inFile:
      List[i]=Line.split(\",\")
         


        

Answer 1

It's a lot easier than that:

List = open("filename.txt").readlines()

This returns a list of each line in the file.

Answer 2

my_list = [line.split(',') for line in open("filename.txt")]