Is it possible to do computation before super() in the constructor?

Question

Given that I have a class Base that has a single argument constructor with a TextBox object as it\'s argument. If I have a class Simple of the following form:

Answer 1

Yes, there is a workaround for your simple case. You can create a private constructor that takes TextBox as an argument and call that from your public constructor.

public class Simple extends Base {
    private Simple(TextBox t) {
        super(t);
        // continue doing stuff with t here
    }

    public Simple() {
        this(new TextBox());
    }
}

For more complicated stuff, you need to use a factory or a static factory method.