Find unique lines

Question

How can I find the unique lines and remove all duplicates from a file? My input file is

1
1
2
3
5
5
7
7

I would like the result to be:

Answer 1

uniq -u has been driving me crazy because it did not work.

So instead of that, if you have python (most Linux distros and servers already have it):

Assuming you have the data file in notUnique.txt

#Python
#Assuming file has data on different lines
#Otherwise fix split() accordingly.

uniqueData = []
fileData = open('notUnique.txt').read().split('\n')

for i in fileData:
  if i.strip()!='':
    uniqueData.append(i)

print uniqueData

###Another option (less keystrokes):
set(open('notUnique.txt').read().split('\n'))

Note that due to empty lines, the final set may contain '' or only-space strings. You can remove that later. Or just get away with copying from the terminal ;)

#

Just FYI, From the uniq Man page:

"Note: 'uniq' does not detect repeated lines unless they are adjacent. You may want to sort the input first, or use 'sort -u' without 'uniq'. Also, comparisons honor the rules specified by 'LC_COLLATE'."

One of the correct ways, to invoke with: # sort nonUnique.txt | uniq

Example run:

$ cat x
3
1
2
2
2
3
1
3

$ uniq x
3
1
2
3
1
3

$ uniq -u x
3
1
3
1
3

$ sort x | uniq
1
2
3

Spaces might be printed, so be prepared!

Answer 2

uniq -u < file will do the job.

Answer 3

uniq has the option you need:

   -u, --unique
          only print unique lines

$ cat file.txt
1
1
2
3
5
5
7
7
$ uniq -u file.txt
2
3

Answer 4

This was the first i tried

skilla:~# uniq -u all.sorted  

76679787
76679787 
76794979
76794979 
76869286
76869286 
......

After doing a cat -e all.sorted

skilla:~# cat -e all.sorted 
$
76679787$
76679787 $
76701427$
76701427$
76794979$
76794979 $
76869286$
76869286 $

Every second line has a trailing space :( After removing all trailing spaces it worked!

thank you

Answer 5

sort -d "file name" | uniq -u

this worked for me for a similar one. Use this if it is not arranged. You can remove sort if it is arranged