URL building with Flask and non-unique handler names

Question

Flask provides a url_for function to generate URLs to handlers based on the URL pattern. But this would imply that the handler functions must have unique names across the en

Answer 1

I don't know how you could do with all the views routed by the same module.

What I usually do is separate my views in different modules (like you did with module A and B), and register them as blueprints, after that, when using the url_for() function, you can prefix the view name with your blueprint name and then avoid conflicts and potential problems.

Here is an example:

main_views.py:

from flask import Blueprint
main = Blueprint('main', __name__)

@main.route('/')
def index():
    pass

admin_views.py:

from flask import Blueprint
admin = Blueprint('admin', __name__)

@admin.route('/admin')
def index():
    pass

application.py:

from flask import Flask
from main_views import main
from admin_views import admin

app = Flask('my_application')
app.register_blueprint(main)
app.register_blueprint(admin)

Now, to access the 2 index views and still distinguish one from the other, just use url_for('main.index') or url_for('admin.index')

EDIT:

Just one more useful details about routing using blueprints, when registering the blueprint, you can pass a url_prefix argument, that will apply to every view within this blueprint.

For example, given the following code:

admin_views.py

from flask import Blueprint
admin = Blueprint('admin', __name__)

@admin.route('/')
def index():
    pass

@admin.route('/logout')
def logout():
    pass

application.py:

from flask import Flask
from admin_views import admin

app = Flask('my_application')
app.register_blueprint(admin, url_prefix='/admin')

The 2 views would be available at the URL /admin/ and /admin/logout