How to Track the Online Status of Users of my WebSite?

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星月不相逢 2020-12-23 02:43

I want to track users that are online at the moment.

The definition of being online is when they are on the index page of the website which has the chat function.

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  • 2020-12-23 02:57

    I have not tried this, so take it with a grain of salt: Set an event handler for window.onunload that notifies the server when the user leaves the page. Some problems with this are 1.) the event won't fire if the browser or computer crashes, and 2.) if the user has two instances of the index page open and closes one, they will appear to logout unless you implement reference counting. On its own this is not robust, but combined with Jonathan's polling method, should allow you to have pretty good response time and larger intervals between updates.

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  • 2020-12-23 02:59

    The question is tagged as "jquery" - what about a javascript solution? Instead of meta/refresh you could use window.setInterval(), perform an ajax-request and provide something "useful" like e.g. an updated "who's online" list (if you consider that useful ;-))

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  • 2020-12-23 03:04

    In the general case, there's no way to know when a user leaves your page.

    But you can do things behind the scenes such that they load something from your server frequently while they're on the page, eg. by loading an <iframe> with some content that reloads every minute:

    <meta http-equiv="refresh" content="60">
    

    That will cause some small extra server load, but it will do what you want (if not to the second).

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  • 2020-12-23 03:06

    Full Solution. Start-to-finish.

    If you only want this working on the index.php page, you could send updates to the server asynchronously (AJAX-style) alerting the server that $_SESSION["userid"] is still online.

    setInterval("update()", 10000); // Update every 10 seconds
    
    function update() {
      $.post("update.php"); // Sends request to update.php
    }
    

    Your update.php file would have a bit of code like this:

    session_start();
    if ($_SESSION["userid"])
      updateUserStatus($_SESSION["userid"]);
    

    This all assumes that you store your userid as a session-variable when users login to your website. The updateUserStatus() function is just a simple query, like the following:

    UPDATE users 
    SET lastActiveTime = NOW()
    WHERE userid = $userid
    

    So that takes care of your storage. Now to retrieve the list of users who are "online." For this, you'll want another jQuery-call, and another setInterval() call:

    setInterval("getList()", 10000) // Get users-online every 10 seconds
    
    function getList() {
      $.post("getList.php", function(list) {
        $("listBox").html(list);
      });
    }
    

    This function requests a bit of HTML form the server every 10 seconds. The getList.php page would look like this:

    session_start();
    if (!$_SESSION["userid"])
      die; // Don't give the list to anybody not logged in
    
    $users = getOnlineUsers(); /* Gets all users with lastActiveTime within the
                                  last 1 minute */
    
    $output = "<ul>";
    foreach ($users as $user) {
      $output .= "<li>".$user["userName"]."</li>";
    }
    $output .= "</ul>";
    
    print $output;
    

    That would output the following HTML:

    <ul>
      <li>Jonathan Sampson</li>
      <li>Paolo Bergantino</li>
      <li>John Skeet</li>
    </ul>
    

    That list is included in your jQuery variable named "list." Look back up into our last jQuery block and you'll see it there.

    jQuery will take this list, and place it within a div having the classname of "listBox."

    <div class="listBox"></div>
    

    Hope this gets you going.

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  • 2020-12-23 03:06

    Well, how does the chat function work? Is it an ajax-based chat system?

    Ajax-based chat systems work by the clients consistently hitting the chat server to see if there are any new messages in queue. If this is the case, you can update the user's online status either in a cookie or a PHP Session (assuming you are using PHP, of course). Then you can set the online timeout to be something slightly longer than the update frequency.

    That is, if your chat system typically requests new messages from the server every 5 seconds, then you can assume that any user who hasn't sent a request for 10-15 seconds is no longer on the chat page.

    If you are not using an ajax-based chat system (maybe Java or something), then you can still accomplish the same thing by adding an ajax request that goes out to the server periodically to establish whether or not the user is online.

    I would not suggest storing this online status information in a database. Querying the database every couple of seconds to see who is online and who isn't is very resource intensive, especially if this is a large site. You should cache this information and operate on the cache (very fast) vs. the database (very slow by comparison).

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  • 2020-12-23 03:06

    The ultimate solution would be implementing something with websockets.

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