Palindrome Golf

Answer 1

With C# and LINQ operators:

public bool IsPalindrome(string s)
{
    return s.Reverse().SequenceEqual(s);
}

If you consider Reverse as cheating, you can do the entire thing with a reduction:

public bool IsPalindrome(string s)
{
    return s.Aggregate(new StringBuilder(),
                       (sb, c) => sb.Insert(0, c),
                       (sb) => sb.ToString() == s);
}

Answer 2

73 clean, readable, chars written in java

boolean p(String s){return s.equals(""+new StringBuffer(s).reverse());}

peace :)

Answer 3

At the risk of getting down votes, most all of these just call a command reverse of some sort that hides all the real programming logic.

I wonder what the shortest manual way to do this is in each of these languages.

Answer 4

F# (a lot like the C# example)

let p s=let i=0;let l=s.Length;while(++i<l)if(s[i]!=[l-i-1]) 0; 1;;

Answer 5

7 characters in J: Not sure if this is the best way, I'm somewhat new to J :)

p=:-:|.

explanation: |. reverses the input. -: compares. the operands are implicit.

p 'radar'
1

p 'moose'
0

Answer 6

I'll take it a little bit further: full c code, compile and go.

90 characters

main(int n,char**v){char*b,*e;b=e=v[1];while(*++e);for(e--;*b==*e&&b++<e--;);return b>e;}