How to copy multiple files and keep the folder structure with Gulp

Question

I am trying to copy files from one folder to another folder using Gulp:

gulp.task(\'move-css\',function(){
  return gulp.src([
    \'./source/css/one.css\',
         


        

Answer 1

I use gulp-flatten and use this configuration:

var gulp = require('gulp'),
    gulpFlatten = require('gulp-flatten');

var routeSources = {
  dist:  './public/',
  app: './app/',
  html_views: {
    path: 'app/views/**/*.*',
    dist: 'public/views/'
  }
};

gulp.task('copy-html-views', task_Copy_html_views);
function task_Copy_html_views() {
  return gulp.src([routeSources.html_views.path])
      .pipe(gulpFlatten({ includeParents: 1 }))
      .pipe(gulp.dest(routeSources.html_views.dist));
}

And there you can see the documentation about gulp-flatten: Link

Answer 2

   gulp.task('move-css',function(){
      return gulp
                  .src([ 'source/**'], { base: './' })
                  .pipe(gulp.dest('./public/assets/css/'));
    });

Your own code didn't include the entire dir tree of source 'source/**' and the base {base:'./'} when calling to gulp.src which caused the function to fail. The other parts where fine.

gulp.task('move-css',function(){
  return gulp.src([
    './source/css/one.css',
    './source/other/css/two.css'

    ]).pipe(gulp.dest('./public/assets/css/'));
});

Answer 3

To achieve this please specify base.

¶ base - Specify the folder relative to the cwd. Default is where the glob begins. This is used to determine the file names when saving in .dest()

---

In your case it would be:

gulp.task('move-css',function(){
  return gulp.src([
      './source/css/one.css',
      './source/other/css/two.css'
  ],  {base: './source/'}) 
  .pipe(gulp.dest('./public/assets/'));
});

Folder structure:

.
├── gulpfile.js
├── source
│   ├── css
│   └── other
│       └── css
└── public
    └── assets