how to convert 2d list to 2d numpy array?

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醉酒成梦
醉酒成梦 2020-12-22 23:28

I have a 2D list something like

a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] 

and I want to convert it to a 2d numpy array. Can we do it without

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  • 2020-12-22 23:53

    I am using large data sets exported to a python file in the form

    XVals1 = [.........] 
    XVals2 = [.........] 
    

    Each list is of identical length. I use

    >>> a1 = np.array(SV.XVals1)
    
    >>> a2 = np.array(SV.XVals2)
    

    Then

    >>> A = np.matrix([a1,a2])
    
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  • 2020-12-23 00:01

    just use following code

    c = np.matrix([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
    matrix([[1, 2, 3],
        [4, 5, 6],
        [7, 8, 9]])
    

    Then it will give you

    you can check shape and dimension of matrix by using following code

    c.shape

    c.ndim

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  • 2020-12-23 00:12

    Just pass the list to np.array:

    a = np.array(a)
    

    You can also take this opportunity to set the dtype if the default is not what you desire.

    a = np.array(a, dtype=...)
    
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  • 2020-12-23 00:13

    np.array() is even more powerful than what unutbu said above. You also could use it to convert a list of np arrays to a higher dimention array, the following is a simple example:

    aArray=np.array([1,1,1])
    
    bArray=np.array([2,2,2])
    
    aList=[aArray, bArray]
    
    xArray=np.array(aList)
    

    xArray's shape is (2,3), it's a standard np array. This operation avoids a loop programming.

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