fs.readFileSync is Not File Relative? Node.js

Question

-Suppose I have a file in the root of my project called \"file.xml\"

-Suppose I have a test file in tests/ called \"test.js\" and it has

const file =         


        

Answer 1

You can resolve the path relative the location of the source file - rather than the current directory - using path.resolve:

const path = require("path");
const file = fs.readFileSync(path.resolve(__dirname, "../file.xml"));