How can I create a border around an Android LinearLayout?

Question

I have one big layout, and one smaller layout inside of it.

How do I create a line border around the small layout?

Answer 1

you can do it Pragmatically also

  GradientDrawable gradientDrawable=new GradientDrawable();
   gradientDrawable.setStroke(4,getResources().getColor(R.color.line_Input));

Then set the background of layout as :

LinearLayout layout = (LinearLayout ) findViewById(R.id.ayout); layout .setBackground(gradientDrawable);

Answer 2

Creat XML called border.xml in drawable folder as below :

<?xml version="1.0" encoding="utf-8"?>
 <layer-list xmlns:android="http://schemas.android.com/apk/res/android">
  <item> 
    <shape android:shape="rectangle">
      <solid android:color="#FF0000" /> 
    </shape>
  </item>   
    <item android:left="5dp" android:right="5dp"  android:top="5dp" >  
     <shape android:shape="rectangle"> 
      <solid android:color="#000000" />
    </shape>
   </item>    
 </layer-list>

then add this to linear layout as backgound as this:

     android:background="@drawable/border"

Answer 3

Try This in your res/drawable

    <?xml version="1.0" encoding="UTF-8"?><layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
  <shape
    android:shape="rectangle">
    <padding android:left="15dp"
        android:right="15dp"
        android:top="15dp"
        android:bottom="15dp"/>
    <stroke android:width="10dp"
        android:color="@color/colorPrimary"/>
  </shape>
</item><item android:left="-5dp"
        android:right="-5dp"
        android:top="-5dp"
        android:bottom="-5dp">
  <shape android:shape="rectangle">
    <solid android:color="@color/background" />
  </shape></item></layer-list>