I have one big layout, and one smaller layout inside of it.
How do I create a line border around the small layout?
Sure. You can add a border to any layout you want. Basically, you need to create a custom drawable and add it as a background to your layout. example:
Create a file called customborder.xml
in your drawable folder:
<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
<corners android:radius="20dp"/>
<padding android:left="10dp" android:right="10dp" android:top="10dp" android:bottom="10dp"/>
<stroke android:width="1dp" android:color="#CCCCCC"/>
</shape>
Now apply it as a background to your smaller layout:
<LinearLayout android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="@drawable/customborder">
That should do the trick.
Also see:
Try this:
For example, let's define res/drawable/my_custom_background.xml as:
(create this layout in your drawable folder) layout_border.xml
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape android:shape="rectangle">
<stroke android:width="2dp" android:height="2dp"
android:color="#FF0000" />
<solid android:color="#000000" />
<padding android:left="1dp" android:top="1dp" android:right="1dp"
android:bottom="1dp" />
<corners android:radius="1dp" android:bottomRightRadius="5dp"
android:bottomLeftRadius="0dp" android:topLeftRadius="5dp"
android:topRightRadius="0dp" />
</shape>
</item>
</layer-list>
main.xml
<LinearLayout
android:layout_gravity="center"
android:layout_width="200dp"
android:layout_height="200dp"
android:background="@drawable/layout_border" />
</LinearLayout>
I'll add Android docs link to other answers.
https://developer.android.com/guide/topics/resources/drawable-resource.html#Shape
It describes all attributes of the Shape Drawable and stroke
among them to set the border.
Example:
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
<stroke android:width="1dp" android:color="#F00"/>
<solid android:color="#0000"/>
</shape>
Red border with transparent background.
This solution will only add the border, the body of the LinearLayout will be transparent.
First, Create this border drawable in the drawable folder, border.xml
<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android= "http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<stroke android:width="2dp" android:color="#ec0606"/>
<corners android:radius="10dp"/>
</shape>
Then, in your LinearLayout View, add the border.xml as the background like this
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:background="@drawable/border">
Don't want to create a drawable resource?
<FrameLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@android:color/black"
android:minHeight="128dp">
<FrameLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_margin="1dp"
android:background="@android:color/white">
<TextView ... />
</FrameLayout>
</FrameLayout>
Create a one xml file in drawable folder
<stroke
android:width="2dp"
android:color="#B40404" />
<padding
android:bottom="5dp"
android:left="5dp"
android:right="5dp"
android:top="5dp" />
<corners android:radius="4dp" />
Now call this xml to your small layout background
android:background="@drawable/yourxml"