Way to get all alphabetic chars in an array in PHP?

Question

Is there a way to get all alphabetic chars (A-Z) in an array in PHP so I can loop through them and display them?

Answer 1

Another way:

$c = 'A';
$chars = array($c);
while ($c < 'Z') $chars[] = ++$c;

Answer 2

Try this :

function missingCharacter($list) {

        // Create an array with a range from array minimum to maximu
        $newArray = range(min($list), max($list));

        // Find those elements that are present in the $newArray but not in given $list
        return array_diff($newArray, $list);
    }
print_r(missCharacter(array('a','b','d','g')));

Answer 3

$alphabets = range('A', 'Z');
    $doubleAlphabets = array();
    $count = 0;
    foreach($alphabets as $key => $alphabet)
    {
        $count++;
        $letter = $alphabet;
        while ($letter <= 'Z') 
        {
            $doubleAlphabets[] = $letter;

            ++$letter;
        }
    }

    return $doubleAlphabets;

Answer 4

PHP has already provided a function for such applications.
chr(x) returns the ascii character with integer index of x.
In some cases, this approach should prove most intuitive.
Refer http://www.asciitable.com/

$UPPERCASE_LETTERS = range(chr(65),chr(90));
$LOWERCASE_LETTERS = range(chr(97),chr(122));
$NUMBERS_ZERO_THROUGH_NINE = range(chr(48),chr(57));

$ALPHA_NUMERIC_CHARS = array_merge($UPPERCASE_LETTERS, $LOWERCASE_LETTERS, $NUMBERS_ZERO_THROUGH_NINE); 

Answer 5

To get both upper and lower case merge the two ranges:

$alphas = array_merge(range('A', 'Z'), range('a', 'z'));

Answer 6

<?php 

$array = Array();
for( $i = 65; $i < 91; $i++){
        $array[] = chr($i);
}

foreach( $array as $k => $v){
        echo "$k $v \n";
}

?>

$ php loop.php 
0 A 
1 B 
2 C 
3 D 
4 E 
5 F 
6 G 
7 H
...