how to open a url in python

Question

import urllib

fun open():
    return urllib.urlopen(\'http://example.com\')

But when example.com opens it does not render css or js. How can I ope

Answer 1

You have to read the data too.

Check out : http://www.doughellmann.com/PyMOTW/urllib2/ to understand it.

response = urllib2.urlopen(..)
headers = response.info()
data = response.read()

Of course, what you want is to render it in browser and aaronasterling's answer is what you want.