how to open a url in python

Question

import urllib

fun open():
    return urllib.urlopen(\'http://example.com\')

But when example.com opens it does not render css or js. How can I ope

Answer 1

You could also try:

import os
os.system("start \"\" http://example.com")

This, other than @aaronasterling ´s answer has the advantage that it opens the default web browser. Be sure not to forget the "http://".

Answer 2

Here is another way to do it.

import webbrowser

webbrowser.open("foobar.com")

Answer 3

with the webbrowser module

import webbrowser

webbrowser.open('http://example.com')  # Go to example.com

Answer 4

import webbrowser  
webbrowser.open(url, new=0, autoraise=True)

Display url using the default browser. If new is 0, the url is opened in the same browser window if possible. If new is 1, a new browser window is opened if possible. If new is 2, a new browser page (“tab”) is opened if possible. If autoraise is True, the window is raised

webbrowser.open_new(url)

Open url in a new window of the default browser

webbrowser.open_new_tab(url)

Open url in a new page (“tab”) of the default browser

Answer 5

I think this is the easy way to open a URL using this function

webbrowser.open_new_tab(url)

Answer 6

On window

import os
os.system("start \"\" https://example.com")

On macOS

import os
os.system("open \"\" https://example.com")

On Linux

import os
os.system("xdg-open \"\" https://example.com")

Cross-Platform

import webbrowser

webbrowser.open('https://example.com')