How to remove an item for a OR'd enum?

Question

I have an enum like:

public enum Blah
{
    RED = 2,
    BLUE = 4,
    GREEN = 8,
    YELLOW = 16
}

Blah colors = Blah.RED | Blah.BLUE | Blah.YELLOW;


        

Answer 1

Thought this might be useful for other people that stumbled here like me.

Be careful how you handle any enum values that you might set to have a value == 0 (sometimes it can be helpful to have a Unknown or Idle state for an enum). It causes problems when relying on these bit manipulation operations.

Also when you have enum values that are combinations of other power of 2 values, e.g.

public enum Colour
{
    None = 0,  // default value
    RED = 2,
    BLUE = 4,
    GREEN = 8,
    YELLOW = 16,
    Orange = 18  // Combined value of RED and YELLOW
}

In these cases an extension method such as this might come in handy:

public static Colour UnSet(this Colour states, Colour state)
{
    if ((int)states == 0)
        return states;

    if (states == state)
        return Colour.None;

    return states & ~state;
}

And also the equivilent IsSet method that handles the combined values (albeit in a bit of a hacky way)

public static bool IsSet(this Colour states, Colour state)
{
    // By default if not OR'd
    if (states == state)
        return true;

    // Combined: One or more bits need to be set
    if( state == Colour.Orange )
        return 0 != (int)(states & state);

    // Non-combined: all bits need to be set
    return (states & state) == state;
}

Answer 2

What about xor(^)?

Given that the FLAG you are trying to remove is there, it will work.. if not, you will have to use an &.

public enum Colour
{
    None = 0,  // default value
    RED = 2,
    BLUE = 4,
    GREEN = 8,
    YELLOW = 16,
    Orange = 18  // Combined value of RED and YELLOW
}

colors = (colors ^ Colour.RED) & colors;

Answer 3

To simplify the flag enum and make it may be better to read by avoiding multiples, we can use bit shifting. (From a good article Ending the Great Debate on Enum Flags)

[FLAG]
Enum Blah
{
   RED = 1,
   BLUE = 1 << 1,
   GREEN = 1 << 2,
   YELLOW = 1 << 3
}

and also to clear all bits

private static void ClearAllBits()
{
    colors = colors & ~colors;
}

Answer 4

The other answers are correct, but to specifically remove blue from the above you would write:

colors &= ~Blah.BLUE;

Answer 5

You can use this:

colors &= ~Blah.RED; 

Answer 6

And not it...............................

Blah.RED | Blah.YELLOW == 
   (Blah.RED | Blah.BLUE | Blah.YELLOW) & ~Blah.BLUE;