How do I use Django with the Tornado web server?
There's a project called tornado-proxy that would help you. But I would like to recommend that you use Nginx. In the Nginx config you could now use proxy_pass to direct your calls like this:
location /comet {
proxy_pass http://localhost:8081;
}
location / {
proxy_pass http://localhost:8080;
}
it's very simple ( especially with django 1.4) .
1 - just build your django project( and apps ) and make sure it works fine.
2- create a new python file at the root folder ( same dir where you used django-admin.py startproject
)
3- then copy the code below , edit the os.environ['DJANGO_SETTINGS_MODULE']
line, and paste it in that new .py file.
import os
import tornado.httpserver
import tornado.ioloop
import tornado.wsgi
import sys
import django.core.handlers.wsgi
#sys.path.append('/home/lawgon/') # path to your project ( if you have it in another dir).
def main():
os.environ['DJANGO_SETTINGS_MODULE'] = 'myProject.settings' # path to your settings module
application = django.core.handlers.wsgi.WSGIHandler()
container = tornado.wsgi.WSGIContainer(application)
http_server = tornado.httpserver.HTTPServer(container)
http_server.listen(8888)
tornado.ioloop.IOLoop.instance().start()
if __name__ == "__main__":
main()
Django 1.6+ it should be like this:
import os
import tornado.httpserver
import tornado.ioloop
import tornado.wsgi
from django.core.wsgi import get_wsgi_application
def main():
os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' # path to your settings module
application = get_wsgi_application()
container = tornado.wsgi.WSGIContainer(application)
http_server = tornado.httpserver.HTTPServer(container)
http_server.listen(8888)
tornado.ioloop.IOLoop.instance().start()
if __name__ == "__main__":
main()
UPDATE:
I created a minimal working demo which shows how to use the Tornado web server to run nicely with django:
https://github.com/tamasgal/django-tornado
ORIGINAL POST:
Just a remark: The WSGI application workflow has been changed from 1.6 to 1.7. You have to replace the import
import django.core.handlers.wsgi
with
from django.core.wsgi import get_wsgi_application
and change the application initialisation from
application = django.core.handlers.wsgi.WSGIHandler()
to
application = get_wsgi_application()
This is the modified code from the Moayyad Yaghi's answer:
import os
import tornado.httpserver
import tornado.ioloop
import tornado.wsgi
import sys
import django.core.handlers.wsgi
from django.core.wsgi import get_wsgi_application
#sys.path.append('/home/lawgon/') # path to your project ( if you have it in another dir).
def main():
os.environ['DJANGO_SETTINGS_MODULE'] = 'myProject.settings' # path to your settings module
application = django.core.handlers.wsgi.WSGIHandler()
application = get_wsgi_application()
container = tornado.wsgi.WSGIContainer(application)
http_server = tornado.httpserver.HTTPServer(container)
http_server.listen(8888)
tornado.ioloop.IOLoop.instance().start()
if __name__ == "__main__":
main()
In real world you would connect Django and some production-ready webserver with WSGI. This demo shows how you can run Tornado (and it's webserver) and Django side by side from one python module serving different URL prefixes: https://github.com/bdarnell/django-tornado-demo. Tornado would block on serving any request directed to Django, though.