Renaming part of a filename [duplicate]

Answer 1

All of these answers are simple and good. However, I always like to add an interactive mode to these scripts so that I can find false positives.

if [[ -n $inInteractiveMode ]]
then
  echo -e -n "$oldFileName => $newFileName\nDo you want to do this change? [Y/n]: "
  read run

  [[ -z $run || "$run" == "y" || "$run" == "Y" ]] && mv "$oldFileName" "$newFileName"
fi

Or make interactive mode the default and add a force flag (-f | --force) for automated scripts or if you're feeling daring. And this doesn't slow you down too much: the default response is "yes, I do want to rename" so you can just hit the enter key at each prompt (because of the ``-z $run\ test.

Answer 2

There are a couple of variants of a rename command, in your case, it may be as simple as

rename ABC XYZ *.dat

You may have a version which takes a Perl regex;

rename 's/ABC/XYZ/' *.dat

Answer 3

Something like this will do it. The for loop may need to be modified depending on which filenames you wish to capture.

for fspec1 in DET01-ABC-5_50-*.dat ; do
    fspec2=$(echo ${fspec1} | sed 's/-ABC-/-XYZ-/')
    mv ${fspec1} ${fspec2}
done

You should always test these scripts on copies of your data, by the way, and in totally different directories.

Answer 4

You'll need to learn how to use sed http://unixhelp.ed.ac.uk/CGI/man-cgi?sed

And also to use for so you can loop through your file entries http://www.cyberciti.biz/faq/bash-for-loop/

Your command will look something like this, I don't have a term beside me so I can't check

for i in `dir` do mv $i `echo $i | sed '/orig/new/g'`

Answer 5

I like to do this with sed. In you case:

for x in DET01-*.dat; do
    echo $x | sed -r 's/DET01-ABC-(.+)\.dat/mv -v "\0" "DET01-XYZ-\1.dat"/'
done | sh -e

It is best to omit the "sh -e" part first to see what will be executed.

Answer 6

for file in *.dat ; do mv $file ${file//ABC/XYZ} ; done

No rename or sed needed. Just bash parameter expansion.