Remove by _id in MongoDB console

Question

In the MongoDB console how can I remove a record by id? Here\'s my collection :

[ 
  {
     \"_id\" : { \"$oid\" : \"4d512b45cc9374271b02ec4f\" },
     \"nam         


        

Answer 1

Do you have multiple mongodb nodes in a replica set?

I found (I am using via Robomongo gui mongo shell, I guess same applies in other cases) that the correct remove syntax, i.e.

db.test_users.remove({"_id": ObjectId("4d512b45cc9374271b02ec4f")})

...does not work unless you are connected to the primary node of the replica set.

Answer 2

Well, the _id is an object in your example, so you just need to pass an object

'db.test_users.remove({"_id": { "$oid" : "4d513345cc9374271b02ec6c" }})'

This should work

Edit: Added trailing paren to ensure that it compiled.

Answer 3

first get the ObjectID function from the mongodb ObjectId = require(mongodb).ObjectID;

then you can call the _id with the delete function

"_id" : ObjectId("4d5192665777000000005490")

Answer 4

Solution and Example:

1- C:\MongoDB\Server\3.2\bin>mongo (do not issue command yet because you are not connected to any database yet, you are only connected to database server mongodb).

2-

show dbs analytics_database 0.000GB local 0.000GB test_database 0.000GB

3-

use test_database switched to db test_database

4-

db.Collection.remove({"_id": ObjectId("5694a3590f6d451c1500002e")}, 1); WriteResult({ "nRemoved" : 1 })

now you see WriteResult({ "nRemoved" : 1 }) is 1 not 0.

Done.

Answer 5

Suppose we have this dummy collection:

{ "_id" : ObjectId("5ea53fedaa79db20d4e14284"), "item" : "planner", "qty" : 75 }

simply use:

db.inventory.deleteOne({ _id: ObjectId("5ea53fedaa79db20d4e14284") })

it will be deleted with this as a response:

{ "acknowledged" : true, "deletedCount" : 1 }

Thats it.