Remove by _id in MongoDB console

Question

In the MongoDB console how can I remove a record by id? Here\'s my collection :

[ 
  {
     \"_id\" : { \"$oid\" : \"4d512b45cc9374271b02ec4f\" },
     \"nam         


        

Answer 1

db.collection("collection_name").deleteOne({_id:ObjectID("4d513345cc9374271b02ec6c")})

Answer 2

Very close. This will work:

db.test_users.deleteOne( {"_id": ObjectId("4d512b45cc9374271b02ec4f")});

i.e. you don't need a new for the ObjectId.

Also, note that in some drivers/tools, remove() is now deprecated and deleteOne or deleteMany should be used instead.

Answer 3

Even though this post is outdated, collection.remove is deprecated! collection.delete_one should be used instead!

More information can be found here under #remove

Answer 4

The answer is that the web console/shell at mongodb.org behaves differently and not as I expected it to. An installed version at home worked perfectly without problem ie; the auto generated _id on the web shell was saved like this :

"_id" : { "$oid" : "4d512b45cc9374271b02ec4f" },

The same document setup at home and the auto generated _id was saved like this :

"_id" : ObjectId("4d5192665777000000005490")

Queries worked against the latter without problem.

Answer 5

I've just bumped into this myself and this variation worked for me:

db.foo.remove({**_id**: new ObjectId("4f872685a64eed5a980ca536")})

Answer 6

If you would like to remove by a list of IDs this works great.

db.CollectionName.remove({
    "_id": {
        $in: [
            ObjectId("0930292929292929292929"),
            ObjectId("0920292929292929292929")
        ]
     }
})