Java program to find the largest & smallest number in n numbers without using arrays

Question

I could get the largest without using arrays but, unable to get the smallest one.

    public static void main(String[] args)
    {
        int smallest=0;
           


        

Answer 1

@user3168844: try the below code:

import java.util.Scanner;

public class LargestSmallestNum {

    public void findLargestSmallestNo() {

        int smallest = Integer.MAX_VALUE;
        int large = 0;
        int num;

        System.out.println("enter the number");

        Scanner input = new Scanner(System.in);

        int n = input.nextInt();

        for (int i = 0; i < n; i++) {

            num = input.nextInt();

            if (num > large)
                large = num;

            if (num < smallest)
                smallest = num;

            System.out.println("the largest is:" + large);
            System.out.println("Smallest no is : "  + smallest);
        }
    }

    public static void main(String...strings){
        LargestSmallestNum largestSmallestNum = new LargestSmallestNum();
        largestSmallestNum.findLargestSmalestNo();
    }
}

Answer 2

import java.util.Scanner;

public class LargestSmallestNumbers {

    private static Scanner input;

    public static void main(String[] args) {
       int count,items;
       int newnum =0 ;
       int highest=0;
       int lowest =0;

       input = new Scanner(System.in);
       System.out.println("How many numbers you want to enter?");
       items = input.nextInt();

       System.out.println("Enter "+items+" numbers: ");


       for (count=0; count<items; count++){
           newnum = input.nextInt();               
           if (highest<newnum)
               highest=newnum;

           if (lowest==0)
               lowest=newnum;

           else if (newnum<=lowest)
               lowest=newnum;
           }

       System.out.println("The highest number is "+highest);
       System.out.println("The lowest number is "+lowest);
    }
}

Answer 3

public static void main(String[] args) {
    int smallest = 0;
    int large = 0;
    int num;
    System.out.println("enter the number");//how many number you want to enter
    Scanner input = new Scanner(System.in);
    int n = input.nextInt();
    num = input.nextInt();
    smallest = num; //assume first entered number as small one
    // i starts from 2 because we already took one num value
    for (int i = 2; i < n; i++) {
        num = input.nextInt();
        //comparing each time entered number with large one
        if (num > large) {
            large = num;
        }
        //comparing each time entered number with smallest one
        if (num < smallest) {
            smallest = num;
        }
    }
    System.out.println("the largest is:" + large);
    System.out.println("Smallest no is : " + smallest);
}

Answer 4

Try the code mentioned below

public static void main(String[] args) {
    int smallest=0; int large=0; int num;
    System.out.println("enter the number");
    Scanner input=new Scanner(System.in);
    int n=input.nextInt();
    num=input.nextInt();
    smallest = num;
    for(int i=0;i<n-1;i++)
        {
            num=input.nextInt();
            if(num<smallest)
            {
                smallest=num;
            }
        }
        System.out.println("the smallest is:"+smallest);
}

Answer 5

Try this...This simple

import java.util.Scanner;

class numbers
{
   public static void main(String args[])
   {
      int x, y, z;
      System.out.println("Enter three integers ");
      Scanner in = new Scanner(System.in);

      x = in.nextInt();
      y = in.nextInt();
      z = in.nextInt();

      if ( x > y && x > z )
         System.out.println("First number is largest.");
      else if ( y > x && y > z )
         System.out.println("Second number is largest.");
      else if ( z > x && z > y )
         System.out.println("Third number is largest.");
      else   
         System.out.println("Entered numbers are not distinct");
   }
}

Answer 6

import java.util.Scanner;

public class LargestSmallestNum {

    public void findLargestSmallestNo() {

        int smallest = Integer.MAX_VALUE;
        int large = 0;
        int num;

        System.out.println("enter the number");

        Scanner input = new Scanner(System.in);

        int n = input.nextInt();

        for (int i = 0; i < n; i++) {

            num = input.nextInt();

            if (num > large)
                large = num;

            if (num < smallest)
                smallest = num;

            System.out.println("the largest is:" + large);
            System.out.println("Smallest no is : "  + smallest);
        }
    }

    public static void main(String...strings){
        LargestSmallestNum largestSmallestNum = new LargestSmallestNum();
        largestSmallestNum.findLargestSmalestNo();
    }
}