I call free(), but the pointer still has data and it's content hasn't changed

Question

The code is below.

My question is about the result. I want to understand, why after calling free(p) p->elem turns to \'0\', but the p->str still contains \"hello\"?

Answer 1

Freeing memory doesn't actually clear the pointer or the memory it pointed to (except under specialized circumstances meant to assist in debugging problems like this -- never rely on the behavior though). Using a pointer after freeing the memory it pointed to is invalid, and is undefined behavior. It might as well crash, or cause random values to be printed.

Also, in C you should not cast the return of malloc.

Answer 2

First, never do that in actual code. Your code works now only because the memory wasn't claimed by other allocations yet, and there's still a "ghost" of the old allocated struct.

On the actual question, your p->str pointer is pointing to a constant literal, i.e. a piece of text which is "hardcoded" in the application data. Hence, the pointer to it will be valid throughout application lifetime - here's a "more valid" example:

p_node p;
p=(p_node)malloc(LEN);
p->elem=99;
p->str="hello";
char* pstr = p->str;
free(p);
printf("the pstr :%s\n",pstr); // still outputs "hello", because pstr would be just a pointer to "hardcoded" data