Swift 3 Optional trouble. Can't unwrap url with passed in string [duplicate]

Answer 1

Your theUrlString is not properly encoded. As a result, when you use URL(string:), it is returning nil (an indication that the URL string passed in was malformed).

I would recommend using URLComponents to create your URL.

Something like:

var urlComponents = URLComponents(string: "http://www.ksl.com/auto/search/index")

var arguments: [String: String] = [
    "keyword": "",
    "make": "Chevrolet",
    "model": "Silverado 1500"
]

var queryItems = [URLQueryItem]()

for (key, value) in arguments {
    queryItems.append(URLQueryItem(name: key, value: value))
}

urlComponents?.queryItems = queryItems

if let url = urlComponents?.url {
    print(url) // http://www.ksl.com/auto/search/index?keyword=&model=Silverado%201500&make=Chevrolet
}

URLComponents API Reference: https://developer.apple.com/reference/foundation/urlcomponents