xslt showing a group of n xml nodes one at a time

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update:

This question has some little xsl code in it !

I\'m struggling with this problem for weeks (even months). I\'m rather beginner throu

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执笔经年

2020-12-22 12:55

Given:

XML

<group>
    <item> 01 </item>
    <item> 02 </item>
    <item> 03 </item>
    <item> 04 </item>
    <item> 05 </item>
    <item> 06 </item>
    <item> 07 </item>
    <item> 08 </item>
    <item> 09 </item>
    <item> 10 </item>
    <item> 11 </item>
    <item> 12 </item>
    <item> 13 </item>
    <item> 14 </item>
    <item> 15 </item>
    <item> 16 </item>
    <item> 17 </item>
    <item> 18 </item>
    <item> 19 </item>
    <item> 20 </item>
    <item> 21 </item>
    <item> 22 </item>
    <item> 23 </item>
    <item> 24 </item>
    <item> 25 </item>
    <item> 26 </item>
</group>

the following stylesheet:

XSLT 1.0

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:param name="pageSize" select="5" />
<xsl:param name="pageNumber" select="3" />

<xsl:template match="/group">
    <html>
        <body>
            <div id="page{$pageNumber}">
                <ul>
                    <xsl:variable name="start" select="$pageSize * ($pageNumber - 1) + 1" />
                    <xsl:for-each select="item[position() >= $start and position() &lt; $start + $pageSize]">     
                        <li>
                            <xsl:value-of select="."/>
                        </li>
                    </xsl:for-each>
                </ul>
            </div>
        </body>
    </html>
</xsl:template>

</xsl:stylesheet>

will return:

Result

<html>
    <body>
        <div id="page3">
            <ul>
            <li> 11 </li>
            <li> 12 </li>
            <li> 13 </li>
            <li> 14 </li>
            <li> 15 </li>
            </ul>
        </div>
    </body>
</html>

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