This is a small piece of code please give a look at it then follow the description....
Peter is trying to explain that you must explicitly specify the property name. Try the following to make your code work:
<project name="demo" default="Mytarget">
<condition property="windoze">
<or>
<equals arg1="${param1}" arg2="win-x86"/>
<equals arg1="${param1}" arg2="win-x86-client"/>
<equals arg1="${param1}" arg2="win-x64"/>
</or>
</condition>
<target name="Mytarget" if="windoze">
<echo message="executing windows family build:::${param1}"/>
</target>
</project>
A better solution would be to make use of operating system tests built into ANT's condition task.
<project name="demo" default="Mytarget">
<condition property="windoze">
<os family="windows"/>
</condition>
<target name="Mytarget" if="windoze">
<echo message="executing windows family build:::${os.name}-${os.arch}-${os.version}"/>
</target>
</project>
Since ant 1.9.1 you can do this:
<project name="tryit" xmlns:if="ant:if" xmlns:unless="ant:unless">
<exec executable="java">
<arg line="-X" if:true="${showextendedparams}"/>
<arg line="-version" unless:true="${showextendedparams}"/>
</exec>
<condition property="onmac">
<os family="mac"/>
</condition>
<echo if:set="onmac">running on MacOS</echo>
<echo unless:set="onmac">not running on MacOS</echo>
</project>
Looks like you misunderstood the Condition Task:
property
: The name of the property to set.
Try using the Conditionos:
Test whether the current operating system is of a given type.