regex : how to match word ending with parentheses “)”

Question

I want to match string ending with \')\' . I use pattern :

 \"[)]\\b\" or \".*[)]\\b\"

It should match the string :

x=main2         


        

Answer 1

If you want to capture a string ending in ) (and not just find a trailing )), then you can use this in JS:

(.*?\)$)

(....) - captures the defined content;

.*? - matches anything up to the next element;

\)$ - a ) at the end of the string (needs to be escaped);

Regex101

Answer 2

The \b only matches a position at a word boundary. Think of it as a (^\w|\w$|\W\w|\w\W) where \w is any alphanumeric character and \W is any non-alphanumeric character. The parenthesis is non-alphanumeric so won't be matched by \b.

Just match a parethesis, followed by the end of the string by using \)$

Answer 3

The \b word boundary is ambiguous: after a word character, it requires that the next character must a non-word one or the end of string. When it stands after a non-word char (like )) it requires a word character (letter/digit/underscore) to appear right after it (not the end of the string here!).

So, there are three solutions:

• Use \B (a non-word boundary): .*[)]\B (see demo) that will not allow matching if the ) is followed with a word character
• Use .*[)]$ with MULTILINE mode (add (?m) at the start of the pattern or add the /m modifier, see demo)
• Emulate the multiline mode with an alternation group: .*[)](\r?\n|$) (see demo)