Regular expression to match US phone numbers

Question

The regular expression ^((\\(\\d{3}\\) ?)|(\\d{3}-))?\\d{3}-\\d{4}$ matches strings of the form XXX-XXX-XXXX and XXX-XXXX (am I missin

Answer 1

Try this:

(\(\d{3}\) )?(\d{3}-){1,2}(\d{4})

Answer 2

I think so this is what you are looking for,

/^((((([0-9]{3})-)|((([0-9]{3}))\s))([0-9]{3})-([0-9]{4}))|(([0-9]{3})-([0-9]{4})))$/

It will work for below patterns XXX-XXX-XXXX, XXX-XXXX, (XXX) XXX-XXXX

Answer 3

^(((\d{3}) ?)|(\d{3}-))?\d{3}-\d{4}$^

this will work.

Answer 4

You need to escape the parenthesis, like this: \( otherwise, they do not get matched and do captures instead.

Answer 5

Your specification is a bit confusing. Your last two cases appear the same:
XXX-XXX-XXXX
XXX-XXXX
(XXX) XXX-XXXX
(XXX) XXX-XXXX

(It looks like you're trying to match a phone number, is that right?) Assuming your last case is "(XXX)XXX-XXXX" (no space between area code and regular number, which I assume is the " ?" meaning optional space) then your RegExp is almost correct, just add two backslashes in front of the area code parentheses so they're matched as plain characters and not special grouping characters:

^((\(\d{3}\) ?)|(\d{3}-))?\d{3}-\d{4}$

Note that your regular expression may not have come through correctly, I noticed that stack overflow removed a single backslash from the RE pattern, I had to type a double backslash "\\" in order to get a single backslash to come out in the message