Which itertools generator doesn't skip any combinations?

Question

When I run this code I don\'t get all the possible combinations of 3 characters:

def comb(iterable, r):
    pool = tuple(iterable)
    n = len(pool)
    for          


        

Answer 1

You're looking for itertools.product(characters, repeat = 3).

See the itertools.product docs.

>>> ' '.join(''.join(x) for x in itertools.product('abcd', repeat = 2))
aa ab ac ad ba bb bc bd ca cb cc cd da db dc dd