Removing Spaces from String in MIPS

Question

I am currently trying to write a code that takes in a string and outputs that same string with no spaces. Everything in my code currently works, but the outputs don\'t delet

Answer 1

Strings are NULL terminated, you should move that terminating NULL to the new end of your string as well.

On a side note, you could do the whole thing in place (for ease in C code:)

#include <stdio.h>

int main() {
  char string1[100];
  fgets (string1, 100, stdin);
  char *inptr = string1; //could be a register
  char *outptr = string1; //could be a register
  do
  {
    if (*inptr != ' ')
      *outptr++ = *inptr;
  } while (*inptr++ != 0); //test if the char was NULL after moving it
  fputs (string1, stdout);
}

Answer 2

This is another way to remove spaces from the sting and print it back. simply loop the string and ignore spaces.

    .text
main:
    li $v0, 4       
    la $a0, prompt
    syscall

    li $v0, 8       
    la $a0, input
    li $a1, 100
    syscall

    move $s0, $a0

loop:
    lb $a0, 0($s0)
    addi $s0, $s0, 1
    beq $a0, 32, loop
    beq $a0, $zero, done    

    li $v0, 11
    syscall

    j loop

done:
    jr $ra

    .data
prompt: .asciiz "Enter a string: "
input: .space 100