getchar not taken in consideration after scanf [duplicate]

Answer 1

You're only having trouble seeing the result because you're starting the program from a windowing environment, and the window closes as soon as its internal tasks are completed. If you run the compiled program from a command line in a pre-existing shell window (Linux, Mac, or Windows), the results will stay on the screen after you're returned to the prompt (unless you've ended by executing a clear-screen of some sort). Even better, in that case, you don't need the extraneous getchar() call.

For Windows, after opening the command prompt window, you'd issue a "cd" command to change to the directory that contains the compiled program, and then type its name. For Linux (and, I presume, Mac, since Mac is UNIX under the hood), you'd need to type ./ ahead of the program name after changing to the appropriate directory with "cd".

Answer 2

scanf("%d",&age);

When the execution of the program reaches the above line,you type an integer and press enter. The integer is taken up by scanf and the \n( newline character or Enter )which you have pressed remains in the stdin which is taken up by the getchar().To get rid of it,replace your scanf with

scanf("%d%*c",&age);

The %*c tells scanf to scan a character and then discard it.In your case,%*c reads the newline character and discards it.

Another way would be to flush the stdin by using the following after the scanf in your code:

while ( (c = getchar()) != '\n' && c != EOF );

Note that c is an int in the above line