PHP - Calling functions with multiple variables [duplicate]

Answer 1

You need to put $var2 and $var3 at the end of the parameter list

function basicFunction ( $var1, $var4 = 5, $var2 = 1, $var3 = 2)

Now you can call:

basicFunction( 0, 3);

Otherwise you will have to specify all of the parameters. When calling functions, you must specify all of the parameters from left to right. The only time you can omit parameters is:

1. If the parameter you want to omit has a default value.
2. All of the parameters to the right of the current parameter have default values.

Answer 2

to skip the values try like this

     $someResult = basicFunction( 0, 0, 0, 3 ); 

or if u have the values set then

       // passing values stored in var2,var3

       $var1 = 1;
       $var2 = 2;

    $someResult = basicFunction( 0, $var1, $var2, 3 );

Answer 3

PHP does not support overloading. Therefore, you cannot skip them in any way if you don't move them to the very right of the list of arguments.

A common solution is to set a default value of a different type than expected (i.e. NULL). The actual default value is then set within the function. This approach is not really clean and takes some extra lines of code, but if the situation requires it, you can go with this:

function basicFunction($var1, $var2 = NULL, $var3 = NULL, $var4 = NULL) {
    if ($var2 === NULL) {
        $var2 = 1;
    }

    // ...