I would like to have a list of those columns of a table that have at least one non-NULL
data entries in them.
In other words, I would like to get the co
Use this procedure this will print columns names of a table which have atleast one not null rows.
create or replace procedure list_col_notNull(tblName in varchar2)
as
lv_col_name varchar2(200);
lv_ctr number;
lv_sql varchar2(400);
CURSOR cur_col_name is
SELECT column_name
FROM USER_TAB_COLUMNS U
WHERE table_name = tblName order by column_name asc;
begin
open cur_col_name;
LOOP
FETCH cur_col_name INTO lv_col_name;
EXIT WHEN cur_col_name%NOTFOUND;
lv_sql := 'select count(1) From ' || tblName || ' where ' || lv_col_name || ' is not null' ;
EXECUTE IMMEDIATE lv_sql into lv_ctr;
if lv_ctr > 0
then
dbms_output.put_line(lv_col_name);
end if;
Create from the INFORMATION_SCHEMA.COLUMNS table a string that contains the SQL you wish to execute, then prepare a statement from that string and execute it.
The SQL we wish to build will look like:
SELECT 'column_a'
FROM table_name
WHERE `column_a` IS NOT NULL
HAVING COUNT(*)
UNION ALL
SELECT 'column_b'
FROM table_name
WHERE `column_b` IS NOT NULL
HAVING COUNT(*)
-- etc.
(One could omit the WHERE
clause and substitute COUNT(*)
for COUNT(column)
, but I think that might be less efficient on indexed columns).
This can be done using the following:
SET group_concat_max_len = 4294967295;
SELECT GROUP_CONCAT(
' SELECT ',QUOTE(COLUMN_NAME),
' FROM table_name',
' WHERE `',REPLACE(COLUMN_NAME, '`', '``'),'` IS NOT NULL',
' HAVING COUNT(*)'
SEPARATOR ' UNION ALL ')
INTO @sql
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = DATABASE()
AND TABLE_NAME = 'table_name';
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
See it on sqlfiddle.