#define many times without #undef,is it legal?

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你的背包 2020-12-21 20:22

For example, I define AA for three times, is it legal?:

#include
#define AA 10
#define AA 20
#define AA 30
int main() {
    printf(\"         


        
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  • 2020-12-21 20:46

    No it is not. The C standard clearly states that it is a constraint violation, 6.10.3 p.2:

    An identifier currently defined as an object-like macro shall not be redefined by another #define preprocessing directive unless the second definition is an object-like macro definition and the two replacement lists are identical.

    So as for all constraint violations, your compiler is only obliged to issue a "diagnostic" that is an explanatory message. It may or may not continue to compile your code.

    To state it more directly, your code erroneous and your compiler must tell you.

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  • 2020-12-21 20:49

    Lets start by correcting your printf to something useful: printf("%d", AA);

    Compiling it with gcc will produce two warnings that "AA" is redefined. Warnings are really important and should be avoided in C, but the result will be as expected (30).

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  • 2020-12-21 20:54

    This is not legal in both C and C++.

    Quotes from draft C standard N1570:

    6.10.3 Macro replacement

    Constraints

    1 Tw o replacement lists are identical if and only if the preprocessing tokens in both have the same number, ordering, spelling, and white-space separation, where all white-space separations are considered identical.

    2 An identifier currently defined as an object-like macro shall not be redefined by another #define preprocessing directive unless the second definition is an object-like macro definition and the two replacement lists are identical. Likewise, an identifier currently defined as a function-like macro shall not be redefined by another #define preprocessing directive unless the second definition is a function-like macro definition that has the same number and spelling of parameters, and the two replacement lists are identical.

    Quotes from draft C++ standard N4582:

    16.3 Macro replacement [cpp.replace]

    1 Two replacement lists are identical if and only if the preprocessing tokens in both have the same number, ordering, spelling, and white-space separation, where all white-space separations are considered identical.

    2 An identifier currently defined as an object-like macro may be redefined by another #define preprocessing directive provided that the second definition is an object-like macro definition and the two replacement lists are identical, otherwise the program is ill-formed. Likewise, an identifier currently defined as a function-like macro may be redefined by another #define preprocessing directive provided that the second definition is a function-like macro definition that has the same number and spelling of parameters, and the two replacement lists are identical, otherwise the program is ill-formed.

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  • It is obviously not recommended even thought it can compile. In your example, you can just use #define AA 30 once. In other cases, if you want to define a macro when it is not defined yet, you can use conditionals:

    #ifndef AA
    #define AA 30
    #endif
    

    Also, I think you mean printf("%d\n", AA); to print the macro, because printf("AA"); will just print the string literal AA.

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