Spring wiring conditional to an environment

Question

With Spring wiring, if I have multiple implementations of an interface, I can use @Qualifier to specify which one I want.

E.g., assuming that I have a

Answer 1

You can injection both implementation and choose which one you need by parameter {spring.profiles.active}, such like this code :

@autowired
private Car Toyota;
@autowired
private Car Bmv;

public Car getCar(){
  if(spring.profiles.active is local){
        return Toyota;
  }else{
        return  bmv;
  }
}

Answer 2

Ah, the solution is actually quite simple:

@Component
@Qualifier("Bmv")
@Profile("!dev")
public class Bmv implements Car

and

@Component
@Qualifier("Toyota")
@Profile("dev")
public class Toyota implements Car

This way, the wiring of Car will use Toyota for dev environment, and Bmv otherwise.

Answer 3

Spring 3.1 introduced environment profiles: http://blog.springsource.com/2011/02/11/spring-framework-3-1-m1-released/

I personally do not like Qualifiers and using them the way you proposed in the code actually couples to the implementation rather than decouple. You can use the @Autowired element like Jason proposed, but couple that with the bean profiles like so:

<beans profile="dev"> <jdbc:embedded-database id="dataSource"> <jdbc:script location="classpath:com/bank/config/sql/schema.sql"/> <jdbc:script location="classpath:com/bank/config/sql/test-data.sql"/> </jdbc:embedded-database> </beans>

and then when you create the environment you specify a profile:

<servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>spring.profiles.active</param-name> <param-value>production</param-value> </init-param> </servlet>