Printing a string value in awk results in error

Question

fatal: not enough arguments to satisfy format string
    `%s SPT=80\'
     ^ ran out for this one

This my code

for ((h = 1 ; h <         


        

Answer 1

The problem is a missing comma in the printf command for awk:

awk -v i=h -v j=17 'FNR == 2 {printf "%s ", $j}' newiptables.log
                                          ^
                                          |== This is needed

Quoting from the manual:

A simple printf statement looks like this:

 printf format, item1, item2, ...